Fig. 2 (b). 12` shows thae distance (S) -time (t) graphs of two trains, which start moving simultaneously in the same direetion. From the graphs, find:
.
(a) How much (B) is ahead of (A) when motion starts
(b) What is the speed of (B) ?
( c) What and where (A) will catch (B) ? `
(d) What is the differnce in speeds of (A) and (B) ? lt

Explanation

(a) When motion starts, (B) is ahead of (A) by the distance `OC= 80 km`.
(b) Speed of `B =(DE)/(CE) =(120-80)/(2-0) =20 km h^(-1)`
(c ) Since the two graphs at point `D, so A` woll catch (B) after 2 ours and at a destance of `120 km` from the origh.
(d) Speed of `A =(DF)/(FO) =(120-0)/(2-0) =60 km h^(-1)`
Differnce in speed `60 -20 40 km h^(-1)`.