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Find the angle of projection at which ho...

Find the angle of projection at which horizontal range and maximum height are equal.

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To find the angle of projection at which the horizontal range and maximum height of a projectile are equal, we can follow these steps: ### Step 1: Write the formulas for maximum height and horizontal range. The maximum height \( h \) of a projectile is given by: \[ h = \frac{u^2 \sin^2 \theta}{2g} \] where \( u \) is the initial velocity, \( \theta \) is the angle of projection, and \( g \) is the acceleration due to gravity. ...
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Knowledge Check

  • The angle of projection at which the horizontal range and maximum height of projectile are equal is

    A
    `45^@`
    B
    `theta = tan^(-1) (0.25)`
    C
    `theta = tan^(-1) (4)`
    D
    `60^(@)`
  • Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

    A
    `alpha = tan^-1(2)`
    B
    `alpha = tan^-1(4)`
    C
    `alpha = tan^-1(5)`
    D
    None of the above
  • If R is the range of a projectiel on a horizontal plane and h its maximum height, the maximum horizontal range with the same velocity of projection is:

    A
    2h
    B
    `(R^(2))/(8h)`
    C
    `2R+(h^(2))/(8R)`
    D
    `2h+(R^(2))/(8h)`
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