A cricket ball is thrown at a speed of ` 28 ms^(-1)` in a direction `30 ^(@)` above the horizontal. Calculate (a)the maximum height (b) the time taken by ball to return ti the same level, and (c )the distance from the thrower to the point wher the ball restance from the throwrt to the point where the ball returns to the same level.

Explanation

To solve the problem step by step, we will break it down into three parts: (a) calculating the maximum height, (b) calculating the time taken for the ball to return to the same level, and (c) calculating the horizontal distance (range) from the thrower to the point where the ball returns.

### Given Data:
- Initial speed \( u = 28 \, \text{m/s} \)
- Angle of projection \( \theta = 30^\circ \)

### Step 1: Calculate the vertical and horizontal components of the initial velocity.
The initial velocity can be resolved into horizontal and vertical components using trigonometric functions.
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