Find the magnitude of the centripetal acceleration of a particle on the tip of a blade, ` 0 .30 ` metre in diameter, rotating at `1200` revolution per minute.

Explanation

Her, `2r =0. 30 m, or r=0.15 m,
`v=(1200)/(60) =20 rps.
Centripetal acceleration , `a© =r omega ^(2) =r (2 pi v) ^(2)`
or `a_(c) =4 pi ^(2) v^(2) r=4 xx xx ((22)/7) ^(2) xx (20) ^(2) xx 0. 15`
`2370 .6 ms^(-2)`.