An object has a uniformly acclerated motion. The object always slows down before the time, when its velcity becomes zero. Establish this statement graphiclly when (i) both initial veocity (u) and acceleration (a) are positive(iii) 9u) is positive and (a) is begative and (iv) both (u) and (a) are negativ e.

Explanation

(i) When both (u) and (a) are positive. In this case, the ` v-t` graph is a straight line as shoen in Fig. 2 (b). 22 (a). In this graph at the time corresponding to point (A), velocity of object becomes zero, From the graph it si clear that before the time corrsponing to point (A), the velcity is negative but its begative magnitude decrease with time till it becomes zero at point (A).
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(ii) When (u) is negative and (a) is positive, In this case, the `v-t` graph is a straight line as shown in Fig. 2 (b) 22 (b). At the time, corresponding to point (A). the velocity becomes zero. From the graph it is clear that before this time, the velocity is negative but irs begative magnitude decreases with time till it becomes zero at point (A).
(iii) When (u) is potive and (a) is negative. Inthis case, the ``v-t` graph is a straight line shown in Fig. 2 (b) .22 (c ).` At the time corresponding to point (A) velocity is zero. From graph it is clear that before this time, corresponding to point (A) the velocity dereases.
(iv) When both (u) and (a) are negative. In this case the ` v-t` graph is a straight line shown in Fig. 2 (b).22 (d) . If we produce his straight line graph backwards, it meets the time axis at point (A) for which velcity is zero. Before this time velocity is positive and dereases till it becomes zero at point (A).