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A ball is dropped vertically from a heig...

A ball is dropped vertically from `a` height `d` above the ground . It hits the ground and bounces up vertically to a height ` (d)//(2). Neglecting subsequent motion and air resistance , its velocity `v` varies with the height `h` above the ground as

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If a ball falls from a height (d) and reaches at height (h) then using the relation, ` v^(2) =u^(2) + 2 a S, we have ` u=0, S=(d-h)` ,
then ` ^(2) =2 g (d-h)`
This relation shows that the variation of (v) and (h) is a parabolec one.
As the ball falls down, its velocity goes on inreasing and becomes maximum at ` h=0`.
As ` h=0`, the direction of velocity is reversed. Then tha ball moves upwards, its velcoity goes on decreasing with height 9h) and becomes zero at ` h= d//2`, The variation of (\v) with (h) will be of the type as shown in Fig. 2 (b) .23.
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