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A weight mg is suspended from the middle...

A weight mg is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. Find the minimum tenstion required to completely straighten the rope.

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See Fig. 2 (c ). 70 , clearly,
2 T sin theta =mg or T= (mg)/ (2 sin theta)`
.
When the porpe is straight, ` theta =0^(@)`,
Then, T= (mg)/ (2 sin 0^(@)) = prop`.
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