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A particle slides down a frictionless pa...

A particle slides down a frictionless paraboli `(y=x^(2))` track `(A-B-C)` starting from rest at point `A`.Point `B` is at the vertex of parabola and point `C` is at a height less than that of point `A`.After `C`,the particle moves freely in air as a projectile. If the particle reaches highest point at `P`,then

A

(a) KE at ` P = KE at B`

B

(b) height at ` P = height at (A)

C

(c ) total eneragy at ` P = total eneragy at (A)`

D

(d) time of travel from ` A` oto ` B = time of travel from (B) tp (P).

Text Solution

Verified by Experts

The correct Answer is:
C
Since ` y= x^2` , the motion is in two dimensions as shown in figure. Velocity at (B) greater than at (P) . In the given motion of a particle, the law of conservation of energy . Therefore, total energy at ` P=` total eneragy at (A). As vertical distance ` ABgt BP`, time of travel from (A) to (B) is greater than that from (B) to (P).
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