Shows the position time graph of a particle of mass 0.04 kg Suggest a suitable physical context for this motion What is the time between two conscutive impulse recevived by the particle ? What is the magnitude of each impulse ?

Explanation

Here , ` m = 0.04 kg `
position time graph in shows that the particle moves from `x = 0` at O to `x = 2` cm at A in 2 seconds . As x - t graph is a straight line , motion is with constant velocity
`u = ((2-0) cm)/((2-0 )s ) = 1 cm//s = 10^(2) m//s`
Again , From `x = 2` cm at A particle goes to x = 0 at B in 2 sec . As AB is a straight line , motion is with constant velocity
`upsilon = - 1 cm// s = - 10^(2) m//s`
Negative sign indicates the reversal of direction of motion This is being repeated We can visualise a ball moving between two walls located at x = 0 and x =2 cm , getting rebounded repeateldly on striking against each wall . On every collision with a wall linear momentum of ball changes . Therefore , the ball receives impulse after every two seconds . Magnitude of each impulse
= total change in linear momentum
` = m (u) - m (upsilon) = m (u- upsilon) `
` = 0 .04 (10^(2) + 10^(2)) = 0.08 xx 10^(2)`
`= 8 xx 10^(-4) kg ms^(-1)`