A wire of mass `9.8 xx 10^(-3)` kg per meter passes over a frictionless pulley fixed on the top of an inclined friction less plane which makes an angle of `30^(@)` with the horizontal Masses `M_(1)` and `M_(2)` are tied at the two ends of the wire The mass `M_(1)` rests on the plane and mass `M_(2)` hangs freely vertically downwards . The whole system is in equilibrium Now a transverse wave propagates along the wire with a velocity of `100 m//s` If `g = 9.8 m//s^(2)` calculate the value of masses `M_(1)` and `M_(2)` .

Explanation

To solve the problem, we need to analyze the forces acting on the two masses \( M_1 \) and \( M_2 \) and use the information about the wave velocity to find their values. Here’s a step-by-step breakdown:

### Step 1: Analyze the Forces
1. **For Mass \( M_2 \)** (hanging vertically):
- The force acting downward is the weight of \( M_2 \): \( M_2 g \).
- The tension \( T \) in the wire acts upward.
- In equilibrium, these forces are balanced:
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