A truck starts from rest and accelerate uniformly with `2 ms^(-2)` . At t = 10 s a stone is dropped by a person standing on the top of the truck (6 m high from ground) . What are the (a) veloctiy and (b) acceleration of the stone at t = 11 s ? Neglect air resistance .

Explanation

To solve the problem step by step, we will break it down into two parts: finding the velocity of the stone at \( t = 11 \) seconds and finding its acceleration at that time.

### Step 1: Calculate the velocity of the truck at \( t = 10 \) seconds

The truck starts from rest and accelerates uniformly. We can use the formula for velocity:

\[
v = u + at
...