Two masses 8 kg and 12 kg are connected at the two ends of a light inextensible string that passes over a frictionless pulley Fibd the acceleration of the masses and tension in the string , when the masses are released
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Explanation

Here , ` m_(2) = 8 kg , m_(1) = 12 kg `
` a = ((m_1-m_(2))g)/(m_1 + m_(2) ) :. a = ((12 -8) 9.8)/(12 + 8 ) = (39.2)/(20) = 1.96 ms^(-2) `
Again ` T = (2m_(1) m_(2) g)/(m_(1) + m_(2)) = (2xx12 xx 8 xx 9.8)/((12 + 8 )) = 94 .1 N ` .