Figure shows the position-time graph of a particle of mass `0.04kg`. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the particle? What is the magnitude of each impluse?

Explanation

Here, `m = 0.04 kg` position time graph shows that the particle moves from x = at O to x = 2 cm at A in 2 sec As x - t graph is a straight line the motion is with a constant velocity
`u = ((2 - 0) cm )/((2 - 0 ) s ) = 1 cm s^(-1) = 10^(-2) ms^(-1)`
From x = 2 cm at A particle goes to x = 0 at B in 2 sec As AB is a straight line , motion is with constant velocity
`v = - 1 cm s^(-1) = - 10^(-2) ms^(-1)`
Negative sign indicates the reversal of direction of motion This is being repeated We can visulise a ball moving between two walls located at x = 0 and x = 2 cm getting rebounded repeatedly on striking against each wall On every collision with a wall linear momentum of the ball changes Therefore the ball receives impulse after every two seconds Magnitude of impulse = total change in linear momentum
` = m u - (m v) = m u - m upsilon = m (u - v) = 0.04 (10^(2)) = 0.08 xx 10^(2) = 8 xx 10^(-4) kg ms^(-1)` .