Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with `1m//s^(-2)` . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is `0.2` upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man`= 65kg (g =9.8m//s^(2))`

Explanation

Here , acceleration of conveyer belt `a = 1 m//s^(2) `
As the man is standing stationary w .r . t. the belt acceleration of the man = acceleration of belt ` = a = 1 m//s^(2)`
As `m = 65 kg `
`:.` Net force on the man , `F' = ma 65 xx 1 = 65 N`
Now `mu = 0.2`
Force of limiting friction `F = mu mg`
If the man remains stationary upto max acc a of the belt then `F = ma = mu mg`
`a = mu g = 0.2 xx 9.8 = 1.96 ms^(-2)`
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