Block `A` of weight `100N` rests on a frictionless inclined plane of slope angle `30^(@)`(Fig. 5.7). `A` flexible cord attached to `A` passes over a frictonless pulled and is connected to block `B` of weight `W`. Find the weight `W` for which the system in equilibrium.

Explanation

As is clear from the system will be in equibrium, when force on block `A` , up the plane is equal to force on `A` down the inclined Plane
`W = mg sin 0 = mg sin 30^(@) = 100 xx(1)/(2) = 50 N`
.