The length of a steel wire increases by `0*5cm` , when it is loaded with a weight of `5*0kg`. Calculate force constant of the wire and workdown in stretching the wire. Take `g=10ms^(-1)`.

Explanation

Here, `x=0*5cm=5xx10^(-3)m, F=5*0kg=50N`
Force constant, `K=(F)/(x)=(50)/(5xx10^(-3)=10^(4)N//m`
Work done in stretching the wire `W=(1)/(2)Kx^(2)=(1)/(2)xx10^(4)(5xx10^(-3))^(2)=(0.25)/(2)=0.125J`