What is the minimum energy released in the annhilation of an electron positron pair?

Explanation

The rest mass of an electron or positron is `m_(0)=9.1xx10^(-31)kg.`
In the annhilation of an electron positron pair, the rest mass of the two particles is converted into energy.
`:.` Minimum energy released,
`E=2m_(0)c^(2)=2(9.1xx10^(-31))(3xx10^(8))^(2)jou l e`.
` E=(2xx9.1xx9xx10^(-15))/(1.602xx10^(-13))MeV=1.02MeV`