A graph of potential energy `V(x)` verses x is shown in figure. A particle of energy `E_(0)` is executing motion in it. Draw graph of velocity and kinetic energy versus x for one complete cycle AFA.

Explanation

Kinetic energy versus x graph
As `KE=E_(0)V_(x)`
`:.` at `A`, `V(x)=E_(0)`
`KE=0`
at `B` `V(x)ltE_(0)`
`:.` KE is `+` but not max.
at `C` and at `D`, `V(x)=0`
`:. ` KE`=` max.
At `F`, `V(x)=E_(0)`
`:.` KE `= 0`
The variation of KE with `x` is as shwon in figure, Velocity versus `x` graph
As `KE=(1)/(2)mupsilon^(2)` `:.` At `A` and `F`, where `KE= 0, upsilon= 0`
At `C` and `D`, KE `=max.` Therefore, `upsilon=+-max.`
At `B` KE is `+` but not maximum.
Therefore, `upsilon=+- ` some value `(lt` max. )
The variation of velocity `upsilon` with `x` is as shown in figure .