An adult weighing 600N raises the centre of gravity of his body by 0.25m while taking each step of 1m lenth in jogging. If he jogs for 6km, calculate the energy utilised by him in jogging assuming that there is no energy loss dur to friction of ground and air. Assuming that the body of the adult is capable of converting `10%` of energy intake in the form of food, calculate the energy equivalent fo food that would be required to compensate energy utilised for jogging.

Explanation

Here, `g=600N, h=0.25m per step`
Number of steps in jogging `=n=(6xx10^(3))/(1)=6xx10^(3)`
Energy utilised in jogging `n(mg)h=6xx10^(3)xx600xx0.25J`
`E=9xx10^(5)J`
This is `10%` of intake, `:.` Intake energy `=10E=9xx10^(6)J`