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Find the centre of mass of three particl...

Find the centre of mass of three particle at the vertices of an equilateral triangle. The masses of the particle are `100g, 150 g, and 200g` respectively. Each side of the equilateral triangle is `0.5m` along.

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To find the center of mass of three particles located at the vertices of an equilateral triangle, we can follow these steps: ### Step 1: Define the coordinates of the particles Let’s denote the particles and their respective masses: - Particle 1 (m1 = 100 g) at vertex A (0, 0) - Particle 2 (m2 = 150 g) at vertex B (0.5, 0) - Particle 3 (m3 = 200 g) at vertex C (0.25, \(0.25\sqrt{3}\)) ...
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Knowledge Check

  • The centre of masses of three particles of mass m_(1) = m_(2)=m_3 = 1 kg at the corners of an equilateral triangle of side 1 m will be -

    A
    0.50m, 0.29m
    B
    0.43m, 0.50m
    C
    0.25m, 0.25m
    D
    0.22m, 0.22m
  • Three masses each of mass m are palced at the vertices of an equilateral triangles ABC of side l as shown in figure. The force acting on a mass 2m placed at the centroid O of the triangle is

    A
    zero
    B
    `(3Gm^(2))/(l^(2))`
    C
    `(5Gm^(2))/(l^(2))`
    D
    `(7Gm^(2))/(l^(2))`
  • Three particles each of mass m are kept at the vertices of an equilateral triangle of side L . What is the gravitational potential at the centroid of the triangle?

    A
    `-(3GM)/(L)`
    B
    `-(sqrt(3)GM)/(L)`
    C
    `-(3sqrt(3)GM)/(L)`
    D
    `-(GM)/(3sqrt(3)L)`
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