A car of mass `2500 kg` is moving in a circular track of diameter `100m` with a speed of `72 km//h`. What is the angular momentum of the car ?

Explanation

Here, `m = 2500 kg`,
`r = (100)/(2)m = 50m`
`upsilon = 72km//h = (72 xx 100)/(60xx 60) = 20m//s`.
`L = ?`
`L = m upsilon r = 2500 xx 20 xx 50`
`= 2.5 xx 10^(6) kg m^(2) s^(-1)`