A flywheel rotating at a speed of `600` rpm about its axis is brough to rest by applying a constant torque for `10` seconds. Find the angular deceleration and angular velocity `5` second after the application of the torque.

Explanation

Here, `n_(1) = 600 "rpm" = (600)/(60) rps`
`= 10 rps`
`n_(2) = 0, t = 10 seconds, alpha = ?`
`alpha = (omega_(2) - omega_(1))/(t) = (2pi(n_(2) - n_(1)))/(t)`
`alpha = (2pi (0 - 10))/(10) = - 2pi rad//s^(2)`
`:.` angular decelartion `= 2 pi rad//s^(2)`
Angain, `omega_(2) = omega_(1) + alpha t :. omega_(2) = 2 pi n_(1) + alpha t`
`omega_(2) = 2 pi xx 10 - 2pi xx 5 = 10 rad//s`