A wheel, initially at rest, rotates for `2 s` under angular acceleration of `3 rad s^(-2)`. Find (i) angular velocity acquired in `2 s`.
(ii) angular displacement in `2 s`.
(ii) torque acting on the wheel if its moment of inertia is `12 kg m^(2)`.

Explanation

Here, `omega_(1) = 0, t = 2s, alpha = 3 rad s^(-2)`
(i) `omega_(2) = omega_(1) + alpha t = 0 + 3 xx 2 = 6 rad s^(-1)`
(ii) `theta = omega_(1)t + (1)/(2) alpha t^(2) = 0 + (1)/(2) xx 3(2)^(2) = 6 rad`
(iii) `tau = I alpha = 12 xx 3 = 36 N-m`.