The maximum and minimum distances of a comet from the sun `1.4 xx 10^(12) m` and `7 xx 10^(10) m`. If its velocity nearest of the sun is `6 xx 10^(4) ms^(-1)`. What is its velocity at the farthest position ? Assume that path of commet in both the instantaneous position is circular.

Explanation

To solve the problem, we will use the principle of conservation of angular momentum. The angular momentum of the comet at its nearest and farthest distances from the Sun will be equal since there are no external torques acting on the system.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Minimum distance from the Sun (R_min) = \(7 \times 10^{10} \, \text{m}\)
- Maximum distance from the Sun (R_max) = \(1.4 \times 10^{12} \, \text{m}\)
- Velocity at minimum distance (V_min) = \(6 \times 10^{4} \, \text{m/s}\)
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