A preson is standing on the centre of a rotating table with his arms outstretched. The table is rotating freely with an angular his hands towards his chest. The moment of inertia reduces to `(3)/(5)` time the original moment of inertia. Calculate angular speed of the man when he withdraws his hands.

Explanation

Let `I_(1) = I, omega_(1) = 24` rpm
`I_(2) = (3)/(5)I, omega_(2) = ?`
According to the law of conservation of angular momentum,
`I_(2)omega_(2) = I_(1)omega_(1)`
`omega_(2) = (I_(1)omega_(1))/(I_(2)) = (I xx 24)/(3//5I) = 40`rpm