Find the moment of inertia of a rectangular bar magent about an axis passing through its centre and parallel to its thickness. Mass of magent is `100 g`, its length is `12 cm`, breadth is `3 cm` and thickness is `2 cm`.

Explanation

Here, `I = ?, m = 100 g`,
`l = 12 cm, b = 3 cm, t = 2 cm`
The axis shown in the Fig. is parallel to thickness of rentangular bar.

`I = m((l^(2) + b^(2))/(12)) = 100 ((12^(2) + 3^(2))/(12))`
`= 100 xx (153)/(12) = 1275 g cm^(2)`