Three balls of masses `1 kg, 2 kg and 3 kg` are arranged at the corners of an equilateral triangle of side `1 m`. What will be the moment of inertia of the system and perpendicular to the plane of the triangle.

Explanation

To find the moment of inertia of the system consisting of three balls of masses 1 kg, 2 kg, and 3 kg arranged at the corners of an equilateral triangle with a side length of 1 m, we will follow these steps:

### Step 1: Identify the Geometry and Masses
We have an equilateral triangle with vertices A, B, and C. The masses are:
- Mass at vertex A (m1) = 1 kg
- Mass at vertex B (m2) = 2 kg
- Mass at vertex C (m3) = 3 kg

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