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The angular speed of a moton wheel is in...

The angular speed of a moton wheel is increased from `1200` rpm to 3120 rpm in `16` seconds. (i) What is the angular acceleration, assuming the acceleration to be uniform ? (ii) How many revolutions does the engine make during this time ?

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To solve the problem step by step, we will break it down into two parts: finding the angular acceleration and calculating the number of revolutions made during the time interval. ### Step 1: Convert angular speeds from rpm to radians per second 1. **Initial Angular Speed (ω_initial)**: \[ \omega_{\text{initial}} = 1200 \text{ rpm} = 1200 \times \frac{2\pi \text{ radians}}{60 \text{ seconds}} = 40\pi \text{ radians/second} \] ...
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The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds, (i) What is its angular acceleration (assume the acceleration to be uniform) (ii) How many revolutions does the wheel make during this time ?

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Knowledge Check

  • The angular speed of a motor wheel is increased from 120 rpm to 3120 rpm in 16 seconds. The angular acceleration of the motor wheel is

    A
    `2 pi rad s^(-2)`
    B
    `4pi rad s^(-2)`
    C
    `6pi rad s^(-2)`
    D
    `8pi rad s^(-2)`
  • The angular speed of a motor wheel is increases from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration of the motor wheel is,

    A
    `2pi " rad " s^(-2)`
    B
    `4 pi " rad " s^(-2)`
    C
    `6 pi " rad "s^(-2)`
    D
    `8 pi " rad " s^(-2)`
  • The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds How many revolutions does the engine make during this time ?

    A
    376
    B
    476
    C
    576
    D
    676
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