An electron revolves around the nucleus of an atom in a circular orbit of radius `4 Å` with a speed of `6.0 xx 10^(6) m//s`. If mass of electron is `9.0 xx 10^(-31) kg`, what is its angular momentum ?

Explanation

Here, `r = 4 xx 10^(-10) m, v = 6.0 xx 10m//s`
`m = 9.0 xx 10^(-31) kg, L = ?`
`L = m v r = 9.0 xx 10^(-31) xx 6.0 xx 10^(6) xx 4 xx 10^(-10)`
`= 2.16 xx 10^(-33) kg m^(2) s^(-1)`