Suppose earth is a point mass of `6 xx 10^(24) kg` revolving around the sun in a circular orbit of diameter `3xx10^(8) km` in time `3.14 xx 10^(7) s`. What is the angular momentum of the eart around the sun ?

Explanation

Here, `m = 6 xx 10^(24) kg`,
`r = (3xx 10^(8))/(2) km = 1.5 xx 10^(11)m`
`T = 3.14 xx 10^(7) s`
`v = (2pi r)/(T) = (2xx3.14 xx 1.5 xx 10^(11))/(3.14 xx 10^(7)) = 3xx 10^(4) m//s`
`L = m v r = 6 xx 10^(24) xx 3xx10^(4) xx 1.5 xx 10^(11)`
`= 2.7 xx 10^(40) kg m^(2) s^(-1)`