The centre of gravity of a loaded texi is `1.5 m` above the ground, and the distance between the wheels is `2m`. What is the maximum speed with which it can go round an unbanked curve of radius `100 m` without being turned upside down. What minimum value of coefficient of friction is needed at this speed ?

Explanation

Applying condition for rotational equilibrium,
`(mv^(2))/(r ) xx h = mg (x), where 2x = 2m, h = 1.5 m`
`v = sqrt((g r x)/(h)) = sqrt((9.8 xx 100 xx 1)/(1.5)) = 25.56 m//s`
`mu = v^(2)//r g = ((25.56)^(2))/(100 xx 9.8) = 0.67`.