A wheel of radius 10 cm can rotate freely about its centre as shown in figure. A stirng is wrapped over its rim and is ulle dby a force of 5.0 N. It is found that the torque roduces an angular acceleration 2.0 `rad/s^2` in the wheel. Calculate the moment of inertia of the wheel.

Explanation

Here, `r = 10 cm = 0.1, F = 5.0 N`,
`alpha = 2.0 rad//s^(2), I = ?` Fig.
Torques due to weight `(W)` of wheel and normal reaction `(R )` at the support are separately zero. The only effective torque is due to firce applied.
As `tau = I alpha`
`:. I = (tau)/(alpha) = (F xx r)/(alpha) = (5 xx 0.1)/(2) = 0.25 kg m^(2)`