A torque of `10^(8)` dyne - cm is applied to a fly wheel of mass `10 kg` and radius of gyration `50 cm`. What is the resultant angular acceleration ?

Explanation

Here, `tau = 10^(8)` dyne-cm
`=(10^(8))/(10^(5)) N xx (1)/(10^(2))m = 10 N-m`
`K = 50cm = (1)/(2)cm = (1)/(2)m, alpha = ? M = 10 kg`
From `tau = I alpha = (MK^(2)) alpha`
`alpha = (tau)/(MK^(2)) = (10)/(10 (1//2)^(2)) = 4 rad//s^(2)`