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The sun rotates around itself once in27 ...

The sun rotates around itself once in`27` days. If it were to expand to twice its present diameter, what would be its new period of revolution ?

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To solve the problem, we need to determine the new period of rotation of the Sun after it expands to twice its present diameter. We will use the principle of conservation of angular momentum. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the initial conditions The Sun completes one rotation in 27 days. This means the initial period of rotation (T) is: \[ T = 27 \text{ days} \] ### Step 2: Determine the initial angular velocity (ω) The angular velocity (ω) can be calculated using the formula: ...
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The time period of rotation of the sun about its axis is 27 days. If the sun expands to thrice of its present diameter, what will be its new period of rotation?

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Knowledge Check

  • If the temperature of the sun becomes twice its present temperature, then

    A
    Radiated energy would be predominantly in infrared
    B
    Radiated energy would be predominantly in ultraviolet
    C
    Radiated energy would be predominantly in X-ray region
    D
    Radiated energy would become twice the present radiated energy

  • If the mass of earth were 4 times the present mass, the mass of the moon were half the present mass and the moon were revolving around the earth at twice the present distance, the time period of revolution of the moon would be (Indays)

    A
    `56sqrt(2)`
    B
    `28sqrt(2)`
    C
    `14sqrt(2)`
    D
    `7sqrt(2)`

  • If earth were to rotate faster than its present speed, the weight of an object

    A
    increases at the equator but remain unchanged at poles
    B
    decreases at the equator but remain unchanged at the poles
    C
    remain unchanged at the equator but decreases at the poles
    D
    remain unchanged at the equator but increases at the poles

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    The sun rotates round itself once in 27 days. What will be period of revolution if the sun were to expand to twice its present radius? Assume the sun to be a sphere of uniform density.

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    Moon takes nearly 27 days to revolve around earth. If the mass od moon is two-third of its present mass, then what will be the period of revolution of moon around earth. Assume that values of all other things remain unchanged.

    If earth contracts to half of its present radius what would be the length of the day at equator ?

    The sun rotates about its axis once in 27 days. If it suddenly shrinks to one-eighth of its original volume, mass remaining same, then what will be its new period of rotation?

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