Calculate moment of inertia of a uniform circular disc of mass `700 g` and diameter `20 cm` about
(i) an axis through the centre of disc and perpendicular to its plane, (ii) a diameter of disc, (iii) a tangent in the plane of the disc, (iv) a tangent perpendicular to the plane of the disc.

Explanation

Here, `M = 700 g, R = (20)/(2) cm = 10 cm`
(i) `I = (1)/(2)MR^(2) = (1)/(2) xx 700 xx 10^(2) = 3.5 xx 10^(4) g cm^(2)`
(ii) `I =(1)/(4)MR^(2) = (1)/(4) xx 700 xx 10^(2)`
`= 1.75 xx 10^(4) g cm^(2)`
(iii) `I = (5)/(4)MR^(2) = (5)/(4) xx 700 xx 10^(2)`
`= 8.75 xx 10^(4) g cm^(2)`
(iv) `I = (3)/(2)MR^(2) =(3)/(2) xx 700 xx 10^(2)`
`= 1.05 xx 10^(5) g cm^(2)`