Two small balls A and B each of mass m, are attched erighdly to the ends of a light rod of length d. The structure rotates about the perpendicular bisector of the rod at an angular speed `omega`. Calculate the angular momentum of the individual balls and of the system about the axis of rotation.

Explanation

As is clear from Fig. velocity of each ball wrt centre `O` is` v = omega(d//2)`, where `r = d//2`.
`:.` Angular momentum of each ball `w.r.t O`,
`L_(1) = L_(2) = mvr = m (omega(d)/(2)) ((d)/(2)) = m omega(d^(2))/(4)`
The angular momentum of the system of two balls.
`L = L_(1) + L_(2) = (1)/(4) m omega d^(2) + (1)/(4) m omega d^(2) = (1)/(2)m omega d^(2)`