A liquid of density `800kg m^(-3)` is filled in a tank open at the top. The pressure of the liquid, at the bottom of the tank is 6.4 atmospheres. The velocity of efflux through a hole at the bottom is (`1atmosphere = 10^(5)Nm^(-2)`)

Options

A. `10ms^(-1)`
B. `20ms^(-1)`
C. `30ms^(-1)`
D. `40ms^(-1)`

Answer

D

Explanation

`v=sqrt(2gh)`
But `h rho g = p :. Hg = (p)/(rho)`
`:.v=sqrt((2p)/(rho)) = sqrt((2xx6.4xx10^(5))/(10^(3))) = 40m//s`.