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A cylindrical tank has a holes of 3 cm^(...

A cylindrical tank has a holes of `3 cm^(2)` in its bottom. If the water is allowed to flow into the tank form a tube above it at the rate of `80 cm^(3)//sec`. Then the maximum height up to which water can rise in the tank is

A

`1.1 cm`

B

`5 cm`

C

`10cm`

D

`0.25 cm`

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The correct Answer is:
To solve the problem, we need to determine the maximum height of water that can rise in a cylindrical tank with a hole at the bottom, given the inflow and outflow rates. ### Step-by-Step Solution: 1. **Identify Given Values**: - Area of the hole at the bottom of the tank, \( A = 3 \, \text{cm}^2 \) - Volume flow rate of water entering the tank, \( Q_{\text{in}} = 80 \, \text{cm}^3/\text{s} \) 2. **Establish the Relationship Between Inflow and Outflow**: - At maximum height, the inflow rate must equal the outflow rate: \[ Q_{\text{in}} = Q_{\text{out}} \] - The outflow rate can be expressed as: \[ Q_{\text{out}} = A \cdot v_{\text{efflux}} \] - Where \( v_{\text{efflux}} \) is the velocity of water flowing out of the hole. 3. **Use Torricelli's Law to Find the Efflux Velocity**: - According to Torricelli's law, the velocity of efflux is given by: \[ v_{\text{efflux}} = \sqrt{2gh} \] - Where \( h \) is the height of the water column above the hole and \( g \) is the acceleration due to gravity (approximately \( 980 \, \text{cm/s}^2 \)). 4. **Set Up the Equation**: - Equating the inflow and outflow rates: \[ Q_{\text{in}} = A \cdot \sqrt{2gh} \] - Substituting the known values: \[ 80 = 3 \cdot \sqrt{2gh} \] 5. **Solve for \( \sqrt{2gh} \)**: - Rearranging gives: \[ \sqrt{2gh} = \frac{80}{3} \] 6. **Square Both Sides**: - Squaring both sides results in: \[ 2gh = \left(\frac{80}{3}\right)^2 \] - Calculating the right side: \[ 2gh = \frac{6400}{9} \] 7. **Solve for Height \( h \)**: - Rearranging for \( h \): \[ h = \frac{6400}{18g} \] - Substituting \( g = 980 \, \text{cm/s}^2 \): \[ h = \frac{6400}{18 \cdot 980} \] - Simplifying gives: \[ h \approx \frac{6400}{17640} \approx 0.362 \, \text{cm} \] ### Final Answer: The maximum height up to which water can rise in the tank is approximately \( 0.36 \, \text{cm} \).

To solve the problem, we need to determine the maximum height of water that can rise in a cylindrical tank with a hole at the bottom, given the inflow and outflow rates. ### Step-by-Step Solution: 1. **Identify Given Values**: - Area of the hole at the bottom of the tank, \( A = 3 \, \text{cm}^2 \) - Volume flow rate of water entering the tank, \( Q_{\text{in}} = 80 \, \text{cm}^3/\text{s} \) ...
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