When the temperature of a gas is raised from `27^(@)C` to `90^(@)C`, the percentage increase in the rms velocity of the molecules will be

Options

A. `10 %`
B. `15 %`
C. `20 %`
D. `17.5 %

Answer

A

Explanation

`(C')/(C) = sqrt((273+90)/(273_+27))+ = sqrt((363)/(300))`
or, `(C')/(C) = sqrt(1.21) = 1.1`
`(C')/(C) -1 = 0.1`
or `(C'-C)/(C) xx 100 = 0.1 xx 100 = 10`.