N molecules , each of mass m, of gas A and 2 N molecules , each of mass 2m, of gas B are contained in the same vessel which is maintained at a temperature T. The mean square volcity of molecules of B type is denoted by ` V_(2)` and the mean square velocity of A type is denoted by `V_(1)` then `(V_(1))/(V_(2))` is

Options

A. `2`
B. `1`
C. `1//2`
D. `2//3`

Answer

A

Explanation

`v_(B) = v = sqrt((3kT)/(2m)) , v_(A) = omega = sqrt((3kT)/(m))`
`(omega^2)/(v^2) = 2`.