A light container having a diatomic gas enclosed with in is moving with velocity v. Mass of the gas is M and number of moles is n. The kinetic energy of gas w.r.t ground is

Options

A. `1/2 MV^(2) + 3/2 nRT`
B. `1/2 MV^(2)`
C. `1/2 MV^(2) + 5/2 nRT`
D. `5/2 nRT`

Answer

C

Explanation

The kinetic energy of gas w.r.t, ground=kinetic energy of centre of mass w.r.t ground+Kinetic energy of gas w.r.t. Centre of mass.
`K.E. = 1/2 MV^(2) +5/2 nRT`.