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When a system is taken from state 1 to 2...

When a system is taken from state `1 to 2` along the path `1 a 2` it absorbs `50 cal` of heat and work done is `20 cal`. Along the path `1 b 2`. `Q = 36 cal`. What is the work done along `1 b 2 ?`

A

`56 cal`

B

`66 cal`

C

`16 cal`

D

`6 cal`

Text Solution

Verified by Experts

The correct Answer is:
D
`dQ = du+dW or Q = (u_(2)-u_(1))+W`
`W = Q_(1b2) (u_(2)-u_(1))`
or, `Q_(1b2) -W = u_(2)-u_(1) = 36-30=6 cal`.
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