The cyclic process for 1 mole of an ideal gas is shown in the V-T diagram. The work done in AB, BC and CA respectively is

Options

A. `0, RT_(2)In((V_1)/(V_2)),R(T_(1)-T_(2))`
B. `R(T_(1)-T_(2)),0,RT_(1)In((V_1)/(V_2)`
C. `0, RT_(2)In((V_2)/(V_1)),R(T_(1)-T_(2))`
D. `0, RT_(2)In((V_2)/(V_1)),R(T_(2)-T_(1))`

Answer

C

Explanation

Process `AB` is isochoric `:. W_(AB) = -(P_(0)V_(0))/(2)`
Precess `BC` is isothermal `:. W_(BC) = RT_(2)*1n((V_2)/(V_1))`
Process `CA` is isobaric
`:. W_(CA) =-PDeltaV = -RDeltaT=-R(T_(1)-T_(2))=R(T_(2)-T_(1))`.