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Suppose 0.5 moles of an ideal gas underg...

Suppose `0.5` moles of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume `V_(f)` versus Q. The temperature of the gas is `(use ln 9 = 2 and R = (25)/(3) J//mol-K)`

A

`293 K`

B

`360 K`

C

`386 K`

D

`412 K`

Text Solution

Verified by Experts

The correct Answer is:
B

`Q = W = nRT 1n(V_f)/(V_i)`
`=T = (Q)/(nR1nV_f//V_i) = (1500)/(0.5xx25/3xx1n3)`
`=(1500)/(0.5xx25//3xx1) = 360K`.
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