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The x -coordinate of the incentre of the...

The x -coordinate of the incentre of the triangle that has the coordinates of mid-points its sides are (0,1), (1,1) and (1, 0) is

A

`2+sqrt(2)`

B

`2-sqrt(2)`

C

`1+sqrt(2)`

D

`1-sqrt(2)`

Text Solution

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The correct Answer is:
To find the x-coordinate of the incenter of the triangle whose midpoints of the sides are given as (0,1), (1,1), and (1,0), we can follow these steps: ### Step 1: Identify the vertices of the triangle The midpoints of the sides of the triangle are given. Let's denote these midpoints as: - A = (0, 1) - B = (1, 1) - C = (1, 0) To find the vertices of the triangle, we can use the fact that the midpoint of a segment is the average of the coordinates of the endpoints. ### Step 2: Find the vertices 1. The midpoint A (0, 1) is the midpoint of the side connecting vertices (x1, y1) and (x2, y2). 2. The midpoint B (1, 1) is the midpoint of another side connecting vertices (x3, y3) and (x4, y4). 3. The midpoint C (1, 0) is the midpoint of the last side connecting vertices (x5, y5) and (x6, y6). By plotting these points, we can deduce the vertices of the triangle: - The vertices can be determined as follows: - The vertex opposite to midpoint A (0, 1) lies on the line connecting (1, 1) and (1, 0). Thus, we can deduce that the vertices are (0, 0), (2, 0), and (0, 2). ### Step 3: Calculate the lengths of the sides Now, we can calculate the lengths of the sides of the triangle: - Length of side opposite to vertex (0, 0): - Distance between (2, 0) and (0, 2) = √[(2-0)² + (0-2)²] = √[4 + 4] = √8 = 2√2 - Length of side opposite to vertex (2, 0): - Distance between (0, 0) and (0, 2) = √[(0-0)² + (2-0)²] = √[4] = 2 - Length of side opposite to vertex (0, 2): - Distance between (0, 0) and (2, 0) = √[(2-0)² + (0-0)²] = √[4] = 2 ### Step 4: Use the formula for the inradius The inradius \( r \) of a triangle can be calculated using the formula: \[ r = \frac{a + b - c}{2} \] Where \( a \), \( b \), and \( c \) are the lengths of the sides of the triangle. Here, we have: - \( a = 2 \) - \( b = 2 \) - \( c = 2\sqrt{2} \) Substituting these values into the formula: \[ r = \frac{2 + 2 - 2\sqrt{2}}{2} = \frac{4 - 2\sqrt{2}}{2} = 2 - \sqrt{2} \] ### Step 5: Determine the x-coordinate of the incenter Since the incenter of a triangle is located at the coordinates (r, r) where r is the inradius, the x-coordinate of the incenter is: \[ x = r = 2 - \sqrt{2} \] ### Final Answer The x-coordinate of the incenter of the triangle is \( 2 - \sqrt{2} \). ---
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