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if one of the lines given by the equation `ax^2+2hxy+by^2=0` coincides with one of the lines given by `a'x^2+2h'xy+b'y^2=0` and the other lines representted by them be perpendicular , then .
`(ha'b')/(b'-a')=(h'ab)/(b-a)=1/2sqrt((-aa'bb')`.

Text Solution

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The correct Answer is:
`(ha'b')/(b'-a')=(h'ab)/(b-a)=1/2 sqrt(-aba'b')`
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