Prove that the triangle formed by the lines `ax^2+2hxy+by^2=0 and lx+my=1 ` isosceles, if `h(l^2-m^2)=(a-b)m `.

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

If a+b=2h, then the area of the triangle formed by the lines ax^(2)+2hxy+by^(2)=0 and the line x-y+2=0, in sq.units is

The lines (lx+my)^2-3(mx-ly)^2=0 and lx+my+n=0 forms

Show that the centroid (x',y') of the triangle with sides ax^2+2hxy+by^2=0 and lx +my =1, is given by (x')/(bl-hm)=(y')/(am-hl)=(2)/(3(am^2-2hlm+bl^2))

if h^2=ab , then the lines represented by ax^2+2hxy+by^2=0 are

If angle between lines ax^(2)+2hxy+by^(2)=0 is (pi)/4 then 2h=

If the acute angle between the lines ax^2+2hxy +by^2=0 is 60^@ then show that (a+3b)(3a+b)= 4h^2