Prove that the lines `2x^2+6xy+y^2=0` are equally inclined to the lines `4x^2+18xy+y^2=0`

If the lines x^(2)+(2+k)xy-4y^(2)=0 are equally inclined to the coordinate axes,then k=

The straight lines represented by the equation 135x^(2)-136xy+33y^(2)=0 are equally inclined to the line x-2y=7 (b) x+2y=7x-2y=4( d) 3x+2y=4

If the two lines kx^(2)+5xy+9y^(2)=0 are equally inclined with the cordinates axes, then: k=

If two lines of x^(2)+3(l-5)xy-5y^(2)=0 are equally inclined with the axes then l=

The angle between the lines x^(2)+4xy+y^(2)=0 is

The combined equation of the lines L_1 and L_2 is 2x^2+6xy+y^2=0 , and that of the lines L_3 and L_4 is 4x^2+18xy+y^2=0 . If the angle between L_1 and L_4 be alpha , then the angle between L_1 and L_3 will be .

If the lines joining the points of intersection of the curve 4x^(2)+9y+18xy=1 and the line y=2x+c the origin are equally inclined to the y-axis,the c is: -1 (b) (1)/(3)( c) (2)/(3)(d)-(1)/(2)

Two lines 9x^(2)+y^(2)+6xy4=0 are

Sum of values of lambda for which pair of lines x^(2)+2 lambda xy+2y^(2)=0 and (1+lambda)x^(2)-8xy+y^(2)=0 are equally inclined to each other is

The lines represented by x^(2)+2lambda xy+2y^(2)=0 and the lines represented by 1+lambda_x^(2)-8xy+y^(2)=0 are equally inclined, then