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Find the equation of the parabola with l...

Find the equation of the parabola with latusrectum joining the points (3,6) and (3,-2).

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To find the equation of the parabola with the latus rectum joining the points (3, 6) and (3, -2), we can follow these steps: ### Step 1: Determine the length of the latus rectum The points given are (3, 6) and (3, -2). Since the x-coordinates are the same (3), we can find the length of the latus rectum by calculating the distance between the y-coordinates. \[ \text{Length} = |y_1 - y_2| = |6 - (-2)| = |6 + 2| = 8 \] ### Step 2: Identify the orientation of the parabola Since the latus rectum is vertical (the x-coordinates are constant), the parabola opens either upwards or downwards. Therefore, the axis of the parabola is parallel to the y-axis. ### Step 3: Find the midpoint of the latus rectum The midpoint of the latus rectum will serve as the focus of the parabola. We can find the midpoint using the formula: \[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{3 + 3}{2}, \frac{6 + (-2)}{2} \right) = \left( 3, \frac{4}{2} \right) = (3, 2) \] So, the focus of the parabola is at (3, 2). ### Step 4: Determine the value of \( A \) The length of the latus rectum is related to \( A \) by the formula \( 4A = \text{Length of latus rectum} \). Thus, we have: \[ 4A = 8 \implies A = \frac{8}{4} = 2 \] ### Step 5: Write the equation of the parabola The standard form of the equation of a parabola that opens upwards or downwards is given by: \[ (y - k)^2 = 4A(x - h) \] Where \( (h, k) \) is the focus. Here, \( h = 3 \) and \( k = 2 \), and we have \( A = 2 \). Substituting these values into the equation gives: \[ (y - 2)^2 = 4 \cdot 2 (x - 3) \] This simplifies to: \[ (y - 2)^2 = 8(x - 3) \] ### Final Answer The equation of the parabola is: \[ (y - 2)^2 = 8(x - 3) \] ---
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ARIHANT MATHS-PARABOLA-Exercise (Questions Asked In Previous 13 Years Exam)
  1. Find the equation of the parabola with latusrectum joining the points ...

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  2. Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y...

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  3. let P be the point (1, 0) and Q be a point on the locus y^2= 8x. The l...

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  4. The axis of parabola is along the line y=x and the distance of its ver...

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  5. The equations of the common tangents to the parabola y = x^2 and y=-...

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  6. The locus of the vertices of the family of parabolas y =[a^3x^2]/3 + [...

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  7. Angle between the tangents to the curve y=x^2-5x+6 at the points (2,0)...

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  8. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

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  9. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

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  10. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

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  11. Statement I The curve y = x^2/2+x+1 is symmetric with respect to the l...

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  12. The equation of a tangent to the parabola y^2=""8x""i s""y""=""x""+...

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  13. Consider the two curves C1 ; y^2 = 4x, C2 : x^2 + y^2 - 6x + 1 = 0 the...

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  14. A parabola has the origin as its focus and the line x=2 as the directr...

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  15. The tangent PT and the normal PN to the parabola y^2=4ax at a point P...

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  16. Let A and B be two distinct points on the parabola y^2 = 4x. If the ax...

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  17. If two tangents drawn from a point P to the parabola y2 = 4x are at ri...

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  18. Consider the parabola y^2 = 8x. Let Delta1 be the area of the triangle...

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  19. Let (x,y) be any point on the parabola y^2 = 4x. Let P be the point t...

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  20. Let (x,y) be any point on the parabola y^2 = 4x. Let P be the point t...

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  21. The shortest distance between line y-x=1 and curve x=y^2 is

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