Home
Class 12
MATHS
Let V be the vertex and L be the latusre...

Let V be the vertex and L be the latusrectum of the parabola `x^2=2y+4x-4`. Then the equation of the parabola whose vertex is at V. Latusrectum `L//2` and axis s perpendicular to the axis of the given parabola.

A

`y^2=x-2`

B

`y^2=x-4`

C

`y^2=2-x`

D

`y^2=4-x`

Text Solution

Verified by Experts

The correct Answer is:
A,C
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    ARIHANT MATHS|Exercise Exercise For Session 1|20 Videos
  • PARABOLA

    ARIHANT MATHS|Exercise Exercise For Session 2|25 Videos
  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|2 Videos
  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|28 Videos

Similar Questions

Explore conceptually related problems

Let A be the vertex and L the length of the latus rectum of the parabola,y^(2)-2y-4x-7=0 The equation of the parabola with A as vertex 2L the length of the latus rectum and the axis at right angles to that of the given curve is:

The length of the latusrectum of the parabola x=ay^(2)+by+c, is

Find equation of a parabola with vertex at (4,-3) and length of latus rectum =4 and axis parallel to x -axis?

If 0 is the vertex and L,L' are the extremities of the latusrectum of the parabola y^(2)=4ax then the area of the triangle OLL' is

Find the equation of the parabola whose vertex is at (2,-3), axis is parallel to x -axis and length of latus rectum is 12

the equation of the parabola whose vertex is origin, axis along y-axis and which passes through the point (4, 2)

End points of the Latusrectum of the parabola (x-h)^(2)=4a(y-k) is

Find the area of the parabola y^(2)=4ax and the latusrectum.

If 4a is the length of latusrectum of the parabola y^(2)-x+4y+5=0 then the value of a is

ARIHANT MATHS-PARABOLA-Exercise (Questions Asked In Previous 13 Years Exam)
  1. Let V be the vertex and L be the latusrectum of the parabola x^2=2y+4x...

    Text Solution

    |

  2. Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y...

    Text Solution

    |

  3. let P be the point (1, 0) and Q be a point on the locus y^2= 8x. The l...

    Text Solution

    |

  4. The axis of parabola is along the line y=x and the distance of its ver...

    Text Solution

    |

  5. The equations of the common tangents to the parabola y = x^2 and y=-...

    Text Solution

    |

  6. The locus of the vertices of the family of parabolas y =[a^3x^2]/3 + [...

    Text Solution

    |

  7. Angle between the tangents to the curve y=x^2-5x+6 at the points (2,0)...

    Text Solution

    |

  8. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

    Text Solution

    |

  9. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

    Text Solution

    |

  10. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

    Text Solution

    |

  11. Statement I The curve y = x^2/2+x+1 is symmetric with respect to the l...

    Text Solution

    |

  12. The equation of a tangent to the parabola y^2=""8x""i s""y""=""x""+...

    Text Solution

    |

  13. Consider the two curves C1 ; y^2 = 4x, C2 : x^2 + y^2 - 6x + 1 = 0 the...

    Text Solution

    |

  14. A parabola has the origin as its focus and the line x=2 as the directr...

    Text Solution

    |

  15. The tangent PT and the normal PN to the parabola y^2=4ax at a point P...

    Text Solution

    |

  16. Let A and B be two distinct points on the parabola y^2 = 4x. If the ax...

    Text Solution

    |

  17. If two tangents drawn from a point P to the parabola y2 = 4x are at ri...

    Text Solution

    |

  18. Consider the parabola y^2 = 8x. Let Delta1 be the area of the triangle...

    Text Solution

    |

  19. Let (x,y) be any point on the parabola y^2 = 4x. Let P be the point t...

    Text Solution

    |

  20. Let (x,y) be any point on the parabola y^2 = 4x. Let P be the point t...

    Text Solution

    |

  21. The shortest distance between line y-x=1 and curve x=y^2 is

    Text Solution

    |